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x^2-4x=1 solve by completing the square
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-4x/2= -2 -2^2=4 (x-2)^2=1+4 x-2=square 5 x= 2 + - square 5
x^2-4x+(4/2)^2=1+(4/2)^2 (x-2)^2=1+4 x-2=+ or - sqrt(5) x=sqrt(5)+2,-sqrt(5)+2
\[(x-2)^{2} = 1+4\] \[(x-2)=\sqrt{5}\] \[x= 2\pm \sqrt{5}\]
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