0.82 = 1e^(3k)

How do I solve for K?

Question

0.82 = 1e^(3k)

How do I solve for K?

anonymous · Answer

Take ln for both sides and you're almost done.

anonymous · Answer

Not quite good with these, as we still didn't study logarithms in school. But I think $$\ln $$ will help solve the thing.

anonymous · Answer

This is right Moe.

anonymous · Answer

Thanks mate. I'll be taking Maths Level 2 Sunject Test in a month, so I'll get to use logarthims quite a bit :)

anonymous · Answer

Good Luck! :)

anonymous · Answer

@remidia, did you get the idea here?

anonymous · Answer

No, this whole problem is really confusing me. The problem in its entirety is

The amount of a drug in a person's bloodstream can be modeled with exponential decay. Suppose that, in 3 hours, 18% of the drug is removed from the bloodstream. What is the half-life of the drug?
A) 8.1 hours B) 8.7 hours C) 9.3 hours D) 9.9 hours E) 10.5 hours