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OpenStudy (anonymous):
so if i have (x-2)(x+1)(x-6)=0 would the answer still be x=2, -1, or 6?
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OpenStudy (anonymous):
All three are answers. Substitute any of them and the entire left expression is zero
OpenStudy (anonymous):
if the problem was (x-2)^2 then the answer would be x=2, right?
OpenStudy (anonymous):
For (x-2)^2=0, yes.
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