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Calculate the tangent line (attached)
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f = x + sqrt (x) Do you know how to take the derivative of a function?
yea, i know to put in the form of y = mx + b but i don't quite remember how to put in the form that he wants...
f' = 1/(2sqrtx) +1
oh, it is in the form y-y1 = m(x - x1) , with y1 moved over by addition.
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so just find the slope at 9 and plug it in
not getting it right,,.
did you get 7/6 ?
nope.. lol which equation did yu use to find that?
f = x - sqrt (x) f' = 1 - 1/2 x^(-1/2) then substitute in 9 for x
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oooh.. solve for y.. alright thankis
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