Question

i need help figuring out how to work this problem. the width of a rectangle is 6 in less than the lengh. the perimeter is 120 in. find the dimensions

Answer 1

let the length be x

Answer 2

then the width is x-6
the perimeter is 2(leng + breadth) = 120
2 (x + x-6) = 120
2x-6 = 60
x=33

Answer 3

ok ty so much

Answer 4

2x+2y = 12 or x+y=60
x=y-6
y + y-6=60
2y=66
y=33
x=27