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Factor the polynomial completely: 2 p 2 − 15 p − 8
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you do the ac method
2*8 = 16 right ?
the first is 2p squared
yes
now find the factors of 16 that combines to b which is -15
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now find the factors of 16 that combines to b which is -15
so 1*-16 is 16 and 1-16 is -15
so you can write the eqn as\[2p^2 + p -16p -8\]
now you do factoring by grouping
okay thank you!
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as so\[p(2p+1) -8(2p+1)\] \[(p-8)(2p+1)\]
medal pwease ? :)
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