A solid generated when region in the first quadrant is enclosed by curves y=2x^2 and y^2=4x is revolved around the x-axis. What is the volume?

A. Pi/5
B. 2Pi/5
C. 8Pi/5
D. 6Pi/5
I got d, but I think I did something wrong. Can anyone else check my answer?

Question

A solid generated when region in the first quadrant is enclosed by curves y=2x^2 and y^2=4x is revolved around the x-axis. What is the volume?

A. Pi/5
B. 2Pi/5
C. 8Pi/5
D. 6Pi/5
I got d, but I think I did something wrong. Can anyone else check my answer?

anonymous · Answer

you've got two bounding equations. y=sqrt(4x) is your upper, and y=2x^2 is your lower. Find your area between them and multiply by 2pi

anonymous · Answer

I got 2/3 as the area between the two functions. If I multiplied it by 2Pi, I would not get any of the answers.