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OpenStudy (anonymous):
how do I solve this by factoring: 4(x-2)/(x-3)+3/x=-3/x(x-3). I figured the lcd is (x-3) and x but once I get to 4x^2-2x+3x-9=-3 I don't know what to do
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OpenStudy (dumbcow):
when you multiplied 4x(x-2) you forgot to multiply the 2 and 4 giving -8x
OpenStudy (dumbcow):
from there add like terms and set equal to zero. Then you can factor
OpenStudy (dumbcow):
i gotta go sorry solution: (x-2)(4x+3) = 0
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