Question

Can anyone tell me how to solve this equation
f(x)=x^3-5X^2+7x+2
were the x values are 0,1,2,3,4,5
Thanks

Answer 1

just plug in those values for x and you'll have the solution

f(0) = 0^3 - 5(0)^2 + 7(0) + 2 = 2

and so on with the others

Answer 2

Thanks for the help when I plug in the 1 I get a -15 is that the same thing you get?

Answer 3

nope. for 1 i get:

f(1)=(1)^3-5(1)^2+7(1)+2
f(1)= 1 - 5 + 7 + 2
f(1)= 5