Question

someone tell me what i did wrong
divide and simplify
z^2-49 divided by 2z-14
------- ------
z^2-8z+16 z^2-2z-63

z^2-49 z^2-2z-63
------ * ----------
z^2-8z+16 2z-14

(z^2-49)(z^2-2z-63)
-------------------
(z^2-8z+16)(2z-14)

this is were im stuck

Answer 1

note that 49 = 7^2
so z^2 -49 = z^2-7^2
also 2z-14 = 2(z-7)
also, you should factorize z^2-8z+16 and z^2-2z-63

Answer 2

so what do i do next

Answer 3

factorize them. do you know how to factorize?

Answer 4

(z-7)(z+7)(z-7)(z+1)
----------------
(z-4)(z+4)(2)(z-7)

Answer 5

no, not entirely correct. try again.

Answer 6

(z-7)(z+7)(z-1)(z+2)(z-7)(z+9)
------------------------
(z-4)(z+4)(2)(z-7)

Answer 7

how did you get 6 terms in your numerator?

Answer 8

-7,7=-49
-1,2=-2
-7,9=-63

Answer 9

yes, but why is the -1,2 = 2 there?

Answer 10

I don't see any need for that.

Answer 11

i thought it was suppose to be when i took it out you said it was wrong

Answer 12

no, I said your factorization was incorrect.

Answer 13

(z^2-49) = (z+7)(z-7)
(z^2-2z-63) = (z-9)(z+7)
(z^2-8z+16) = (z-4)^2
2z-14 = 2(z-7)
I hope you can take it from there.

Answer 14

then rewrite and simplify

(z-7)(z+7)(z-9)(z-7)
----------------
(z-7)(z-4)(2)(z-7)

(z-7)
---- 1*(z+7)(z-9)(z+7)
(z-7) ----------
(z-4)(2)(z-7)