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Mathematics 13 Online
OpenStudy (anonymous):

x = , y =

OpenStudy (anonymous):

OpenStudy (anonymous):

whole large triangle has sides 5, 13 and by pythagoras other side is 12. Whole triangle is similar to small upper triangle so \[\frac{y}{13}=\frac{5}{12}\] or \[y=\frac{13 \times 5}{12}=\frac{65}{12} \]

OpenStudy (anonymous):

WHAT ABOUT X?

OpenStudy (anonymous):

i just got 5.4

OpenStudy (anonymous):

x you find as follows. You know that side containing x is 12. you can find the missing piece since you know two sides of that right triangle with side 5 and hypotenuse 5.4 (rounded) so it is \[\sqrt{5.4^2-5^2}=\sqrt{4.16}=2.04\] subtract from 12 to get 9.96

OpenStudy (anonymous):

how do got 12 as x

OpenStudy (anonymous):

x is not 12. the long side of which x is a portion is 12. that is because the large triangle is a right triangle and you know the length of one side (5) and the hypotenuse (13) so you know \[5^2+ s^2=13^3\] \[s^2=13^2-5^2\] \[s=\sqrt{13^2-5^2}=\sqrt{136-25}=\sqrt{144}=12\]

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