Question

y=(m^2)x+(1/m) is the tangent to the parabola y^2 = 16x for what value of m?

Answer 1

sub first in the second, expand out, you gert quadratic in x , find discriminant and set to zero

Answer 2

putting the equation of tangent in the eqn. of parabola we get
(m^2x+1/m)^2=16x
m^4x^2(2m-16)x+1/m^2=0.
as it is a tangent so discriminant is 0.
(2m-16)^2-4m^2=0 gives you m=4.

Answer 3

please check it.....

Answer 4

the way you type is very annoying

Answer 5

should put brackets around stuff

Answer 6

all right. thanx you guys, that helped.

Answer 7

elecengineer .....i did it to make him understand the problem.....