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find the domain of the function. f(x)=sqrtx2-9
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x^2 >/ 9
x (-inf,-3] u [3,inf)
amister can you help me
(-inf,-3) U (3,inf)
wtsup btm??
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-3 and 3 are included amistre
amortized problem posted
btm, i checked out the amortization and gotta tell ya; still aint up to par wit hthsoe things; they happen to show up at the end of my calc book like they are a part of calc4 or something
\[x^2\geq9\] \[x\geq 3\] or \[x\leq -3\]
ok thanks
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him, i saw that lol
variation of paramaters they call it; and constants and such
they have homogenos and nonhomogenous stuff in there that looks similar to your work :)
so which of all these responses is my solution?
the correct one of course :)
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(-inf,-3] U [3,inf)
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