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Mathematics 24 Online
OpenStudy (anonymous):

find the domain of the function. f(x)=sqrtx2-9

OpenStudy (amistre64):

x^2 >/ 9

OpenStudy (anonymous):

x (-inf,-3] u [3,inf)

OpenStudy (anonymous):

amister can you help me

OpenStudy (amistre64):

(-inf,-3) U (3,inf)

OpenStudy (anonymous):

wtsup btm??

OpenStudy (anonymous):

-3 and 3 are included amistre

OpenStudy (anonymous):

amortized problem posted

OpenStudy (amistre64):

btm, i checked out the amortization and gotta tell ya; still aint up to par wit hthsoe things; they happen to show up at the end of my calc book like they are a part of calc4 or something

OpenStudy (anonymous):

\[x^2\geq9\] \[x\geq 3\] or \[x\leq -3\]

OpenStudy (anonymous):

ok thanks

OpenStudy (amistre64):

him, i saw that lol

OpenStudy (amistre64):

variation of paramaters they call it; and constants and such

OpenStudy (amistre64):

they have homogenos and nonhomogenous stuff in there that looks similar to your work :)

OpenStudy (anonymous):

so which of all these responses is my solution?

OpenStudy (amistre64):

the correct one of course :)

OpenStudy (amistre64):

(-inf,-3] U [3,inf)

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