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Mathematics 14 Online
OpenStudy (anonymous):

Factor by grouping. Factor completely. 32x^3 + 8x^2 + 48x + 12

OpenStudy (anonymous):

\[32x^3 + 8x^2 + 48x + 12=8x^2(4x+1)+12(4x+1)=(4x+1)(8x^2+12)\]

OpenStudy (anonymous):

How'd did you solve it?

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