Question

Solve by completing the square:
3x^2+12x+14=0

Answer 1

3x^2 + 12x + 14 = 0
3(x^2 + 4x + 14/3) = 0
x^2 + 4x + 14/3 = 0
x^2 + 4x = -14/3
x^2 + 4x + (4/2)^2 = -14/3 + (4/2)^2
x^2 + 4x + 4 = -14/3 + 4
(x + 2)^2 = 4 - 14/3
x + 2 = ±sqrt(4 - 14/3)
x = -2 ±sqrt(4 - 14/3)