Question

What is the equation of a line that passes through the point (-3,-11) and is parallel to the line who equation is 2x-y=4?

Answer 1

\[2x-y=4\]
\[y=2x-4\]
line with slope 2, y intercept -4
if the line line you want it parallel it must have the same slope, so use the 'point-slope' formula
\[y-y_1=m(x-x_1)\]
so \[y=(-11)=2(x-(-3))\]
\[y+11=2(x+3)\]
\[y+11=2x+6\]
\[y=2x-5\]

Answer 2

oops typo. first line should be \[y-(-11)=2(x-(-3))\]