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OpenStudy (anonymous):
g^2+2/3g+1/9=0 solve the equation
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OpenStudy (anonymous):
this will factor into (g+1/3)(g+1/3) = 0 so setting the factors equal to 0 g+1/3=0 g=-1/3
OpenStudy (anonymous):
would positive 1/3 be included in that
OpenStudy (anonymous):
nope, because the other factor is also g+1/3 this function touches the x-axis but does not cross it
OpenStudy (anonymous):
ok thanks
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