Question

What is the domain of f(x)=2x-1/ x^2+2x-3

Answer 1

it is \[\frac{2x-1}{x^2+3x-3}\]?

Answer 2

no the bottom is x^2+2x-3

Answer 3

if so, ignore the numerator and find the zeros of the denominator.
\[x^2+2x-3=0\]
\[(x-1)(x+3)=0\]
\[x=1\]
or\[x=-3\]
so all real numbers except 1 and -3