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Mathematics 21 Online
OpenStudy (anonymous):

What is the exact value of cos-1(-1/sqrt2)

OpenStudy (anonymous):

In what quadrants Cosine is -ve? 2nd and 3rd

OpenStudy (anonymous):

let x = cos-1(-1/sqrt2) cos(x) = (-1/sqrt2) now we know x is either in 2nd or in 3rd quadrants

OpenStudy (anonymous):

cos 45 = 1/sqrt2 Sry abt the 3rd Quadrant..cosine is -ve in 2nd quadrant

OpenStudy (anonymous):

so, reference angle is 45 180-45 =135 x= 135 degrees

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