Question

Given cos 2θ=-1/2 and 2θ ends in quadrant II. Find cotθ

Answer 1

1) solve for \[\theta\]
\[2\Theta=4\pi/3\]
\[\theta=2\pi/3\]
it's means that:
\[\cot \theta =\cot (2\pi/3)=(-1/2) /(\sqrt{3}/2) = -1/\sqrt{3}\]