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y=x^2-x-6 Must...Find...Roots! One root is (-2,0) and i think the other is...(4,0)?
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If you plug in 4 for x, do you get 0 for y?
If so then 4 is a root. If not, then it's not.
Thanks :)
\[16-4-6 \ne 0\]
now i gotta do the long way with quadratic formula....Ugh
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I think you can factor pretty easy.
What two numbers multiply to give -6 and add to give -1?
Hmm.. So (3,0) and (-2,0)...?!
Lets see: 9 - 3 - 6 = 0 so yep.
Yay.
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