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OpenStudy (anonymous):
Differentiate: y=(3x+2)^cos(x)
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OpenStudy (anonymous):
\[D\left[(2+3 x)^{\text{Cos}[x]},x\right]=(2+3 x)^{\text{Cos}[x]} \left(\frac{3 \text{Cos}[x]}{2+3 x}-\text{Log}[2+3 x] \text{Sin}[x]\right) \]
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