Ask
your own question, for FREE!
Mathematics
13 Online
OpenStudy (anonymous):
Please need help. Ill send a prob in pic.
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
help what?
OpenStudy (anonymous):
are you good at geometry?
OpenStudy (anonymous):
I don't so so If not too hard I help my son geometry now I can try
OpenStudy (anonymous):
OpenStudy (anonymous):
ive replied in ur earlier question
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
i see. don't get the answer tho.
OpenStudy (anonymous):
plug in 16 for a
OpenStudy (anonymous):
i still don't get it. i SUCK at math.
OpenStudy (anonymous):
see il explain
OpenStudy (anonymous):
doesn' say angles degree , but given use square 3 I can tell,
hypotenuse = twice time shot leg
16/2=8
than CB = 8*2=16
\[\sqrt{3}* 16= the heigh\]
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
if u drop a perpendicular to a base from any vertex, it divides ur equilateral triangle into two halves
OpenStudy (anonymous):
if the side of your equilateral triangle is a, the base of each of these 2 triangles is a/2
OpenStudy (anonymous):
\[\sqrt{3}* 8 \]not 16 sorry
OpenStudy (anonymous):
like him say the side divi haft triangle
16/2=8
the heigh = square3* 8
CB=8*2=16
OpenStudy (anonymous):
\[\sqrt{16^{2}-8^{2}}=13.9\]
A=(16*13.9)/2
A=111.2
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
Arriyanalol:
bro how
3 days ago
1 Reply
2 Medals