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solve for x... x^2+6x+8=0 and 3x^2+6x=0
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from 3x^2+6x=0 we get x = -3x^2 / 6 = -x^2 / 2 subtituting x = -x^2/2 to x^2+6x+8=0 x^2 + 6(-x^2/2) +8 = 0
Woah.. Im using Generic Rectangles to figure this out. Lol
But this will still work i think.
what is generic rectangles ? because im not native english
\[x^2+6 x+8=(x+2) (x+4)=0 \]
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I'm assuming you want to find x for each separate equation. For: x^2+6x+8=0 (x+4)(x+2)=0 x=-4 and x=-2 For: 3x^2+6x=0 3x(x+2)=0 3x=0 x=0 and x=-2 for (x+2)
oh that's a different equation,
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