A line passes through the points (-6, 3) and (x2, y2), and has a slope of 5/10. If point (x2, y2) is located in quadrant I, find x2.

4
-12
-7
-5

Question

A line passes through the points (-6, 3) and (x2, y2), and has a slope of 5/10. If point (x2, y2) is located in quadrant I, find x2.

4 
  -12 
  -7 
  -5

anonymous · Answer

any ideas

anonymous · Answer

theres one piece of info missing

anonymous · Answer

2y - 6 = x+6
x2 = 2y2 -12

anonymous · Answer

this is all the problem says

anonymous · Answer

u need the value of y2

anonymous · Answer

the answer was 4 i went ahead and guessed

anonymous · Answer

guessing wont do u good...in the long term

anonymous · Answer

ive been n childrens hospital. I have missed all the explaining and my teacher exspects me to know it all. and its harder then she thinks.

anonymous · Answer

no prob..dont worry...were to help

anonymous · Answer

Thanks

anonymous · Answer

its obvious it had to be 4 lols , its the only positive answer, and for the point to be in the first quadrant then x must be positive

anonymous · Answer

oh that way..lol

anonymous · Answer

lol. How can they ask such questions? :D Neways good luck jessmaynard!