Question

tan²θ-√3tanθ=0. find solutions in the interval [0,360°). Round to the nearest ten minutes.
Help!

Answer 1

\[tan^2(\theta)-\sqrt{3}tan(\theta)=0\]
\[tan(\theta)(tan(\theta)-\sqrt{3})=0\]
\[tan(\theta)=0\]or
\[tan(\theta)=\sqrt{3}\]

Answer 2

of course you still have to solve for \[\theta\]

Answer 3

\[tan(\theta)=0\]
\[\theta=0\]

Answer 4

\[tan(\theta)=\sqrt{3}\]
\[\theta=\frac{\pi}{3}\]
or \[\theta=\frac{4\pi}{3}\]
of you ar working in degrees instead of radians it would be 60 and 240