Question

is Sin(A)=-sqrt(7)/4 and CosB=-sqrt(3)/3, find the value of Sin(A-B). Can you help me please ...

Answer 1

sinn(a-b)= sina* cos b - cosa* sinb

Answer 2

but I dont have cos(A). How do I do

Answer 3

tht mean we wanna cos A by sina^2+cosa^2=1
cos a = 1- (7/16)
=3/4

& sin b by the same way = sqrt(6)/3

Answer 4

ok now
sin (a-b)= -sqrt7/4 * -sqrt(3)/3 - 3/4 * sqrt(6)/3
=sqrt (21)/12 - 3sqrt(6)/12
= \[\sqrt{}\]

Answer 5

=(sqrt (7) -3 / 4*sqrt(3) )
is it clear??

Answer 6

let me check it out

Answer 7

ok take ur time
hope i can help u

Answer 8

yes sure. Youre helping me a lot

Answer 9

Got it. Thanks It is very clear my friend

Answer 10

ok , may allah bless u

Answer 11

:)