Question

Two vertices of a regular tetrahedron are located at A= (0,0,0) and B= (1, 0, 0) The centroid is at X= (1/2, (√3)/6, (√6)/12). What is the measure of angle AXB, to the nearest degree?

Answer 1

REPEAT sorry!

Answer 2

Just kidding, my feed is glitching!

Answer 3

Find vector AX and vector BX

Answer 4

Let's call the vectors u and v. To find the angle\[udotv=||u||||v||\cos \theta\]