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Consider the given curves to do the following x=4sqrt(y) x=0 y=1 Use the method of cylindrical shells to find the volume V of the solid obtained by rotating the region bounded by the given curves about the x-axis.
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A(y) = 2pi*y*(4sqrt(y)) \[V=2\pi \int\limits_{0}^{1}4y \sqrt{y} dy\] \[=8\pi \int\limits_{0}^{1} y ^{3/2} dy\] \[=\frac{16}{5}\pi\]
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