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Mathematics 21 Online
OpenStudy (anonymous):

csc θ + cot θ/sin θ = sin θ + cos θ/sin²θ . Show that this is an identity.

OpenStudy (anonymous):

You have placed the parenthesis at the wrong place

OpenStudy (anonymous):

It should have been (csc θ + cot θ)/sin θ = (sin θ + cos θ)/sin²θ

OpenStudy (anonymous):

csc θ + (cot θ/sin θ) = (sin θ + cos θ)/sin²θ . Show that this is an identity.… help?

OpenStudy (dumbcow):

cot = cos/sin csc = 1/sin sin/sin^2 = 1/sin 1/sin + cos/sin^2 = 1/sin + cos/sin^2

OpenStudy (anonymous):

csc θ + (cot θ/sin θ) = (sin θ + cos θ)/sin²θ . Show that this is an identity.… help?

OpenStudy (dumbcow):

i already showed how they are equal

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