Can some one please help me with Permutations and Combinatorics. The question is A farmer has 3 children and a herd of 27 cows. He gives 8 cows to his oldest child and 4 cows to his youngest child. Find the number of different ways the farmer can split up his herd.

Question

Can some one please help me with Permutations and Combinatorics.  The question is A farmer has 3 children and a herd of 27 cows.  He gives 8 cows to his oldest child and 4 cows to his youngest child.  Find the number of different ways the farmer can split up his herd.

anonymous · Answer

27C8 x 19C4

anonymous · Answer

how did you get that though im confused

anonymous · Answer

the first child, picks 8 from the 27

then we have 19 left , then the second picks 4 from this 19

then the third child get whatevers left over ( ie they choose 15 out of the 15 remaining )

but 15C15 is one, so you just multiply by 1

anonymous · Answer

Thanks but i still dont get it lol

anonymous · Answer

whats not to get :|

anonymous · Answer

its actually one of the easiest combinations questions you will come across

anonymous · Answer

cause im dumb when it comes to math

anonymous · Answer

he gave us a take home quiz with 5questions and i cant even solve one of them thats sad lol