Question

Add. Simplify by removing factors of 1if possible
28zx + z-7x
----- -----
z^2-49x^2 z+7x
I dont know how to do the exponents without this ^

Answer 1

I think I might've solved it! :-) 28zx/2z+14x

Answer 2

But do you have the result somewhere to double check for me?

Answer 3

The way I did it is:

28zx/(z-7x)(z+7x) + z-7x/z+7x Explanation: (z-7x) with z-7x are reduced...you just cross them out and then you just add them together 28zx remains alone on the top si on the bottom we have z+7x + z+7x which equals 2z+14x so that's why I came up with the answer as being 28zx/2z+14x. It would've been good to know if you had the response somewhere at the end of the book so we can double check the answer.

Answer 4

Nope, that's no the right answer. It can be done though..., that's all I know for now.

Answer 5

i dont its a question on my practice test

Answer 6

I'm still working on it! :)

Answer 7

28zx+1
--------
z+7x

Answer 8

It's 28zx+z^2+49x^2 :D

Answer 9

This is definitely the answer! :P I knew it can be done!

Answer 10

But it must be simplified some more though. :P

Answer 11

Just a second... :D

Answer 12

mowrey almost had it right to begin with. When you cancel don't forget the 1that is there when you cancel

Answer 13

Final result! z^2+14xz+49x^2

Answer 14

I get an answer of (z+7x)/(z-7x). Here is how I arrived at the answer:

28zx/(z^2-49x^2) + (z-7x)/(z+7x) Factor the bottom left term to get:

28zx/(z-7x)(z+7x) + (z-7x)/(z+7x) Now find a common denominator to get:

[(28zx + (z-7x)(z-7x)]/(z-7x)(z+7x)
(28zx+z^2-14zx+49x^2)/(z-7x)(z+7x)
(z^2+14zx+49x^2)/(z-7x)(z+7x) Factor the top term to get:

(z+7x)(z+7x)/(z-7x)(z+7x) = (z+7x)/(z-7x)

Answer 15

Nah, it's still going! I have this (z^2+14xz+49x^2) / (z^2-49x^2)...

Answer 16

mowrey the same my answer

Answer 17

wait almost ,

Answer 18

Yes, and it goes down to your answer! :) (z+7x)/(z-7x)

Answer 19

Very good radar! You're the man!

Answer 20

I mean gw2011...sorry! :D

Answer 21

Man, what an exercise...! :D I've been struggling with it since she posted it the first time...several hours ago!

Answer 22

28zx z-7x
------- + ------
z^2-49x^2 z+ 7x

28zx z-7x
---------- + --------
(z+7x)(z-7x) z+x

28zx (z-7x)(z-7x)
-------- + -----------
(z+7x)(z-7x) (z+7x)(z-7x)

28zx + z^2-14zx+49x^2
------------------------------
(z+7x)(z-7x)

z^2+14zx+49x^2
----------------
(z+7x)(z-7x)

(z+7x)(z+7x)
------------
(z+7x)(z-7x)

z+7x
------
z-7x

Answer 23

I started with the same mistake "cancelling" when I shouldn't lol

Answer 24

gw2011 did it right.

Answer 25

Yes, he was the first to post the result! :D