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\[\sqrt{16r^7s^5}+7r^2\sqrt{r^3s^5}-6rs \sqrt{r^5s^3}\]
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\[\sqrt[5]{16x ^{13}y^8}\times \sqrt[5]{4xyz ^{10}}\]
o.k are u here?
so you can look at the whole thin as being under the root
one way that i tackle these problems is that i like to put the radical as fractions
\[\sqrt{a}=a ^{1/2}\]
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in this case the nth root is 5, so it would be \[a^{1/5}\]
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