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Write the quadratic equation in the variable x having the given numbers as solutions. the equation is standard form, ax^2+bx+c=0
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solution:5, only solution
x=\[(-b \pm \sqrt{b^2-4ac})/(2a)\]
sorry
\[x ^{2}-10x+25\]=0
solution:6, only solution
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\[x ^{2}-12x+36=0\]
\[(x-6)^{2}=0\]
use one since same...x-6=0 add 6 to both sides and get x=6
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