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"Dave and Jane wells have a new rectanular driveway. The perimeter of the driveway is 168 feet. The length is 12 feet longer than three times the width. What are the dimensions of the driveway?"
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thats easy ,
How would you set it up?
let x be width, y be length
Perimeter = 2x + 2y = 168 , one eqn
but we also know that y=3x+12
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2eqns , 2 unknowns easy to solve
so divide the first by 2 x + y = 84 --- eqn 1 y=3x+12 --eqn2
sub 2 into 1 4x + 12 = 84 4x = 72 x= 18 sub that value into eqn 2 y= 3(18) + 12 = 54 +12 = 66
width=18ft, length = 66ft
thank you so much
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