Question

F(t)=12sint, [0,9π/2]

Answer 1

what do u want with this?

Answer 2

?????????

Answer 3

calculate the avergae value of the function F(t)=12sint, across the interval [0,9π/2]

I have the answer but dont understand how to get the end answer

Answer 4

\[=\frac{1}{9\pi/2}12\int\limits_{0}^{9\pi/2}\sin t dt\]

Answer 5

thanks dumb cow :D

Answer 6

welcome
glad that helped
its same formula whenever you need avg value

Answer 7

sweet :D:D:D
will be very useful :D