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how to find p if the distance between (p,3) and (-1,2p) is 5 units? ?
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could use vectors maybe?
or just distance it lol
but how?
(p+1)^2 +(3-2p)^2 = 5^2
p^2 +2p +1 +9 +4p^2 -12p = 25
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6p^2 -10p +10 - 25 = 0 6p^2 -10p -15 = 0 solve for p
either complete the square method or quadratic formula it
:) thx man... btw I feel awfully dumb after reading this... thx again
:) anytime you wanna feel the fool; come on by :)
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