how do i solve this inequality if it looks like y > x
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OpenStudy (amistre64):
whatever you put in for x; make sure y is bigger.... its an area of a graph with a boundary at the y=x line
OpenStudy (amistre64):
OpenStudy (anonymous):
all value of y should olwaYs be greater than the value of x. thyen it is true.!
OpenStudy (anonymous):
ok thanks
OpenStudy (anonymous):
for you to be easy. all positve integer(y) > all negative integer(x) not equal to Zero.
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OpenStudy (anonymous):
how do i solve a system with a x^2 like heres the equation \[y \ge x^{2}-1\]
OpenStudy (amistre64):
graph the line y = x^2-1
pick a point NOT ON THE LINE and test to see if it makes the inequaltiy true of false.
if true; shade that side, if false shade the other side
OpenStudy (anonymous):
ok ., are you familiar with the cartecian plane?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
you can graph that one ., through the cartecian plane.,, by substituting the corresponding of value of (x).
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OpenStudy (amistre64):
OpenStudy (anonymous):
i think you will come up that one into a parabola.,. f i'm not mistaken.