Question

find the equation of the path described by the following vector.

u=t^2+4/(t+2)^2 + 4t/(t+2)^2

Answer 1

thats a mean looking vector

Answer 2

lol yeah

Answer 3

the left side is usually the 'x' component; which leaves the other to be the 'y' component

Answer 4

they have the same bottoms on i see that

Answer 5

it gives a hint to factorise but im not sure how to use it

Answer 6

t^2 +4 + 4t (t+2)(t+2)
------------ = --------- = 1
(t+2) (t+2) (t+2)(t+2)

Answer 7

y = 1 with a hole at -2 i think

Answer 8

x+y = 1

y = -x then

Answer 9

lol the answers is y=1-x

Answer 10

...... or that lol

Answer 11

wait yeah thats right

Answer 12

didnt see the second answer lol

Answer 13

it is? como es posible?

Answer 14

lol thanks heaps ur a genius