Question

tan((cos^-1)(6x)) exact answer use radicals as needed

Answer 1

=0?

Answer 2

will it be tan(0) right?

Answer 3

can you write the equation again pls, what is cos^-1?? is it equal to 0?

Answer 4

(\[\tan(\cos ^{-1}6x)\]

Answer 5

and what is this equal to?

Answer 6

i suppose 0 it didnt say in my problem

Answer 7

well without that it is hard :)

Answer 8

alright :)

Answer 9

you have to use that tan x=0 at 0+kPi (k integer)

Answer 10

so you want to have cos^-1(6x)=0