Question

solve.

2log4-log3+2logx-4=0

Answer 1

2log4-log3+2logx-4=0
Equivalent to \[\log(16/3)+\log(x ^{2})=4\]
then \[\log(16x ^{2}/3)=4\]
you will get \[x^{2}=10^{4}\times3\div16\]
solve using calculator you will get 43.3 (1 decimal)