Question

algebra can you help me with # 2 and # 3 thanks

Answer 1

the cooking one?

Answer 2

yes please

Answer 3

cook has 4 quarts that is 50% chicken stock. so at the moment it is 50% of 4 = 2 quarts chicken stock. so for example if she adds 3 quarts of chicken stock she will have 4+3= 7 quarts of liquid of which 2 + 3 = 5 quarts is chicken stock, and the percent will be 5/7 * 100. this is not what you want obviously, i am just trying to explain where the equation will come from.

if she adds x quarts of chicken stock she will have 2+x quarts of chicken stock and 4+x quarts of liquid. you want
\[\frac{2+x}{4+x}=.75\]
\[2+x=.75(4+x)\]
last equation says your two quarts of chicken stock plus your x quarts must be 75% of the total liquid. now we solve
multiply out
\[x+2=.75x+.75\times 4= .75x+3\]
\[.25x=1\]
subtract .75x from both sides and subtract 2 from both sides
\[x=\frac{1}{.25}=\frac{100}{25}=4\]

Answer 4

and #3 thanks

Answer 5

ok #3 looks like the previous one we did so let me be careful and not put the 1 on the wrong side like i did last time.

Answer 6

keep seeming to put the 1 on the wrong side. you have two rates, r and r +1

\[\frac{12}{r}=\frac{12}{r+1}+1\]
slower person's time is one less more than faster persons.
\[\frac{12}{r}=\frac{12+r+1}{r+1}=\frac{r+13}{r+1}\]
cross multiply\[12(r+1)=r(r+13)\]
\[12r+12=r^2+13r\]
\[r^2+r-12=0\]
\[(r+4)(r-3)=0\]
\[r=3\]
\[r=-4\]
so r = 3