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OpenStudy (anonymous):
If an object is thrown upward with an initial velocity of 10 ft per second, then its height is given by h = -10t2 + 40t. What is its maximum height?
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OpenStudy (anonymous):
you need to find vertex of h
OpenStudy (anonymous):
-b/2a
OpenStudy (anonymous):
-40/2(-10) =2 plug that into function -10(2)^2 +40(2)
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