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how would i go about solving 8e^2x=20
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natural log cancels the e. Then solve normally.
divide by 8, take the log, divide by 2
Like 8/20 first. Then ln e^2x, and you get 2x=ln(20/8). Then you divide all tht by 2 and that's the answer.
I mean 20/8
\[8e ^{2x} = 20\] \[\ln (20/8) = 2x\] \[ x= .5*\ln(20/8) = \ln(\sqrt{2.5})\]
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thank youuuuuuuu
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