Question

4x2 - 8x + 5y2 + 30y - 41 = 0
A) The graph is the point (-1, 3).
B) The graph is an ellipse with center (1, -3).
C) The graph is a circle with center (1, -3).
D) The equation has no graph.

Answer 1

it is definitely not a circle since we have the coefficients of x^2 and y^2 do not equal
it is likely to be an ellipse since the sign of x^2 is the same as the sign of y^2, but there could also be no graph
now we are required to do more thinking

Answer 2

i will eat and if someone else hasnt answer i will look at is some more k?

Answer 3

thx

Answer 4

hey try to write it like this [(x-1)^2]/5+[(y+3)^2]/4=9/2
this an ellsipse since the RHS is not negative

Answer 5

the center is (1,-3)

Answer 6

also if the RHS was zero after writing it in that form this would the graph of the point
(1,-3)