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OpenStudy (anonymous):
divide 18x^3-33x^2-39x-9/6x 3
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OpenStudy (anonymous):
Need order of operations. How is it written on paper? Is the 6x in the denominator of the entire expression? Did you mean 6*3?
OpenStudy (anonymous):
sorry its 6x+3
OpenStudy (anonymous):
18x^3 - 33x^2 - 39x - 9 is the numerator and 6x + 3 is the denominator?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
Factor out a 3 from 6x+3 first. Then divide each front term in the numerator (18,-33,-39,-9) by 3, and put that over (2x+1).
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OpenStudy (anonymous):
ive done that, so what should my final answer look like?
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