Question

factor s^6-729

Answer 1

its a difference of cubes

Answer 2

\[\sqrt[3]{729} =9 \]

Answer 3

\[a=s^2 , b=9 \]\[a^3 -b^3 = (a-b)(a^2 +ab +b^2) \]

where

Answer 4

\[(s^2-9)(s^4 +9s^2+81) \]

Answer 5

now


and that factors to \[(s-3)(s+3)(s^2-3s+9)(s^2+3s+9)\]