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simplify 1. (1/7)-^2 2. -7^2 3. (-7)^2
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the answer is # 1
3 separate problems
oh so what have you done so far? what part are you lost?
i seems like all are either -1/-49 or -49.
hmm ok for number 1 when you have anything like this \[A ^{-b}\] = \[\frac{1}{A^b}\] so for the first do that and it should be easy to solve it
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for the second the - sign is outside the 7 so you scared 7 first and then multiply it with the - sign
for the third its simply (-7) *(-7)
a. = \[\frac{1}{49} \] b. = \[-49\] c. = 49
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