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Find the inverse of the function. P(x)=x
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\[P(x)=\sqrt{x}\]
what do you do when you inverse?
take away
wrong
the inverse of x is just x so you have P(x) = y = x swap x with y and solve for y x= y y=x the inverse is itself
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\[y= \sqrt{x}\] is the inverse function for the function y=x^2 on interval \[[0, \infty)\]
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