Question

integrate 1/ (8x-x^2)^(1/2)

Answer 1

integral (8x-x^2)^(-1/2) dx

Answer 2

You complete the square for the denominator of the fraction. You should end up with the fraction 1/(16 - (x-4)^2)^(1/2). Using the arc sin rule for integration your answer would be arc sin((x-4)/4) + c. Hope that helps.

Answer 3

Thnk you :)) Sorry its a late reply